4(4v-6)+3v=2(v+9)

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Solution for 4(4v-6)+3v=2(v+9) equation: 



4(4v-6)+3v=2(v+9)

We move all terms to the left:

4(4v-6)+3v-(2(v+9))=0

We add all the numbers together, and all the variables

3v+4(4v-6)-(2(v+9))=0

We multiply parentheses

3v+16v-(2(v+9))-24=0



We calculate terms in parentheses: -(2(v+9)), so:

2(v+9)

We multiply parentheses

2v+18

Back to the equation:

-(2v+18)



We add all the numbers together, and all the variables

19v-(2v+18)-24=0

We get rid of parentheses

19v-2v-18-24=0

We add all the numbers together, and all the variables

17v-42=0

We move all terms containing v to the left, all other terms to the right

17v=42

v=42/17

v=2+8/17

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