x(x-17)-18x=(x-30)(x+16)

Solution for x(x-17)-18x=(x-30)(x+16) equation:

x(x-17)-18x=(x-30)(x+16)

We move all terms to the left:

x(x-17)-18x-((x-30)(x+16))=0

We add all the numbers together, and all the variables

-18x+x(x-17)-((x-30)(x+16))=0

We multiply parentheses

x^2-18x-17x-((x-30)(x+16))=0

We multiply parentheses ..

x^2-((+x^2+16x-30x-480))-18x-17x=0


We calculate terms in parentheses: -((+x^2+16x-30x-480)), so:

(+x^2+16x-30x-480)

We get rid of parentheses

x^2+16x-30x-480

We add all the numbers together, and all the variables

x^2-14x-480

Back to the equation:

-(x^2-14x-480)


We add all the numbers together, and all the variables

x^2-35x-(x^2-14x-480)=0

We get rid of parentheses

x^2-x^2-35x+14x+480=0

We add all the numbers together, and all the variables

-21x+480=0

We move all terms containing x to the left, all other terms to the right

-21x=-480

x=-480/-21

x=22+6/7