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(x-4)(x-8)=x-14
We move all terms to the left:
(x-4)(x-8)-(x-14)=0
We get rid of parentheses
(x-4)(x-8)-x+14=0
We multiply parentheses ..
(+x^2-8x-4x+32)-x+14=0
We add all the numbers together, and all the variables
(+x^2-8x-4x+32)-1x+14=0
We get rid of parentheses
x^2-8x-4x-1x+32+14=0
We add all the numbers together, and all the variables
x^2-13x+46=0
a = 1; b = -13; c = +46;
Δ = b2-4ac
Δ = -132-4·1·46
Δ = -15
Delta is less than zero, so there is no solution for the equation
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