4(4r-3)-6=36-2r

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Solution for 4(4r-3)-6=36-2r equation: 



4(4r-3)-6=36-2r

We move all terms to the left:

4(4r-3)-6-(36-2r)=0

We add all the numbers together, and all the variables

4(4r-3)-(-2r+36)-6=0

We multiply parentheses

16r-(-2r+36)-12-6=0

We get rid of parentheses

16r+2r-36-12-6=0

We add all the numbers together, and all the variables

18r-54=0

We move all terms containing r to the left, all other terms to the right

18r=54

r=54/18

r=3

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