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10=2/3(3m-6)
We move all terms to the left:
10-(2/3(3m-6))=0
Domain of the equation: 3(3m-6))!=0We multiply all the terms by the denominator
m∈R
-(2+10*3(3m-6))=0
We calculate terms in parentheses: -(2+10*3(3m-6)), so:We add all the numbers together, and all the variables
2+10*3(3m-6)
determiningTheFunctionDomain 10*3(3m-6)+2
Wy multiply elements
30m(3+2
Back to the equation:
-(30m(3+2)
-(30m5=0
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