3(4b+8)=2(3b-4)

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Solution for 3(4b+8)=2(3b-4) equation: 



3(4b+8)=2(3b-4)

We move all terms to the left:

3(4b+8)-(2(3b-4))=0

We multiply parentheses

12b-(2(3b-4))+24=0



We calculate terms in parentheses: -(2(3b-4)), so:

2(3b-4)

We multiply parentheses

6b-8

Back to the equation:

-(6b-8)



We get rid of parentheses

12b-6b+8+24=0

We add all the numbers together, and all the variables

6b+32=0

We move all terms containing b to the left, all other terms to the right

6b=-32

b=-32/6

b=-5+1/3

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