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4(3x-5)-2(7-3x)=6(2x-3)-5(2-3x)
We move all terms to the left:
4(3x-5)-2(7-3x)-(6(2x-3)-5(2-3x))=0
We add all the numbers together, and all the variables
4(3x-5)-2(-3x+7)-(6(2x-3)-5(-3x+2))=0
We multiply parentheses
12x+6x-(6(2x-3)-5(-3x+2))-20-14=0
We calculate terms in parentheses: -(6(2x-3)-5(-3x+2)), so:We add all the numbers together, and all the variables
6(2x-3)-5(-3x+2)
We multiply parentheses
12x+15x-18-10
We add all the numbers together, and all the variables
27x-28
Back to the equation:
-(27x-28)
18x-(27x-28)-34=0
We get rid of parentheses
18x-27x+28-34=0
We add all the numbers together, and all the variables
-9x-6=0
We move all terms containing x to the left, all other terms to the right
-9x=6
x=6/-9
x=-2/3
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