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9-5z=12-6(6z/7)
We move all terms to the left:
9-5z-(12-6(6z/7))=0
We add all the numbers together, and all the variables
-5z-(12-6(+6z/7))+9=0
We multiply all the terms by the denominator
-5z*7))-(12-6(+6z+9*7))=0
We add all the numbers together, and all the variables
-5z*7))-(12-6(6z+63))=0
We add all the numbers together, and all the variables
-5z*7))-(12-6(6z=0
Wy multiply elements
-35z^2=0
a = -35; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-35)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$z=\frac{-b}{2a}=\frac{0}{-70}=0$
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