1/5(4(k+2)-(3-k)=4

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Solution for 1/5(4(k+2)-(3-k)=4 equation: 



1/5(4(k+2)-(3-k)=4

We move all terms to the left:

1/5(4(k+2)-(3-k)-(4)=0



Domain of the equation: 5(4(k+2)-(3-k)-4!=0

k∈R



We add all the numbers together, and all the variables

1/5(4(k+2)-(-1k+3)-4=0

We multiply all the terms by the denominator


1!=0

There is no solution for this equation

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