4(3x-3)+4(-x)=2+(-x)+7x

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Solution for 4(3x-3)+4(-x)=2+(-x)+7x equation: 



4(3x-3)+4(-x)=2+(-x)+7x

We move all terms to the left:

4(3x-3)+4(-x)-(2+(-x)+7x)=0

We add all the numbers together, and all the variables

4(3x-3)+4(-1x)-(2+(-1x)+7x)=0

We multiply parentheses

12x-4x-(2+(-1x)+7x)-12=0



We calculate terms in parentheses: -(2+(-1x)+7x), so:

2+(-1x)+7x

determiningTheFunctionDomain
(-1x)+7x+2

We add all the numbers together, and all the variables

7x+(-1x)+2

We get rid of parentheses

7x-1x+2

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We add all the numbers together, and all the variables

8x-(6x+2)-12=0

We get rid of parentheses

8x-6x-2-12=0

We add all the numbers together, and all the variables

2x-14=0

We move all terms containing x to the left, all other terms to the right

2x=14

x=14/2

x=7

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