4(3x+5)=40+7x

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Solution for 4(3x+5)=40+7x equation: 



4(3x+5)=40+7x

We move all terms to the left:

4(3x+5)-(40+7x)=0

We add all the numbers together, and all the variables

4(3x+5)-(7x+40)=0

We multiply parentheses

12x-(7x+40)+20=0

We get rid of parentheses

12x-7x-40+20=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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