1/(x+1)-1/(4-x)=0

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Solution for 1/(x+1)-1/(4-x)=0 equation: 



1/(x+1)-1/(4-x)=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (4-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-4

x!=-4/-1

x!=+4

x∈R



We add all the numbers together, and all the variables

1/(x+1)-1/(-1x+4)=0

We calculate fractions


(1*(-1x+4))/((x+1)*(-1x+4))+(-1*(x+1))/((x+1)*(-1x+4))=0



We calculate terms in parentheses: +(1*(-1x+4))/((x+1)*(-1x+4)), so:

1*(-1x+4))/((x+1)*(-1x+4)

We multiply all the terms by the denominator


1*(-1x+4))

Back to the equation:

+(1*(-1x+4)))





We calculate terms in parentheses: +(-1*(x+1))/((x+1)*(-1x+4)), so:

-1*(x+1))/((x+1)*(-1x+4)

We multiply all the terms by the denominator


-1*(x+1))

Back to the equation:

+(-1*(x+1)))

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