x(9x-3)=(9x+8)(x-1)

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Solution for x(9x-3)=(9x+8)(x-1) equation: 



x(9x-3)=(9x+8)(x-1)

We move all terms to the left:

x(9x-3)-((9x+8)(x-1))=0

We multiply parentheses

9x^2-3x-((9x+8)(x-1))=0

We multiply parentheses ..

9x^2-((+9x^2-9x+8x-8))-3x=0



We calculate terms in parentheses: -((+9x^2-9x+8x-8)), so:

(+9x^2-9x+8x-8)

We get rid of parentheses

9x^2-9x+8x-8

We add all the numbers together, and all the variables

9x^2-1x-8

Back to the equation:

-(9x^2-1x-8)



We add all the numbers together, and all the variables

9x^2-3x-(9x^2-1x-8)=0

We get rid of parentheses

9x^2-9x^2-3x+1x+8=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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