4(3x+4)-(2x+1)=-12-(3x-1)

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Solution for 4(3x+4)-(2x+1)=-12-(3x-1) equation: 



4(3x+4)-(2x+1)=-12-(3x-1)

We move all terms to the left:

4(3x+4)-(2x+1)-(-12-(3x-1))=0

We multiply parentheses

12x-(2x+1)-(-12-(3x-1))+16=0

We get rid of parentheses

12x-2x-(-12-(3x-1))-1+16=0



We calculate terms in parentheses: -(-12-(3x-1)), so:

-12-(3x-1)

determiningTheFunctionDomain
-(3x-1)-12

We get rid of parentheses

-3x+1-12

We add all the numbers together, and all the variables

-3x-11

Back to the equation:

-(-3x-11)



We add all the numbers together, and all the variables

10x-(-3x-11)+15=0

We get rid of parentheses

10x+3x+11+15=0

We add all the numbers together, and all the variables

13x+26=0

We move all terms containing x to the left, all other terms to the right

13x=-26

x=-26/13

x=-2

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