(3x-3)(x-16)=0

Solution for (3x-3)(x-16)=0 equation:

(3x-3)(x-16)=0

We multiply parentheses ..

(+3x^2-48x-3x+48)=0

We get rid of parentheses

3x^2-48x-3x+48=0

We add all the numbers together, and all the variables

3x^2-51x+48=0

a = 3; b = -51; c = +48;
Δ = b2-4ac
Δ = -512-4·3·48
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-45}{2*3}=\frac{6}{6}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+45}{2*3}=\frac{96}{6}
=16
$