6(y-5)=3(10+3y)

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Solution for 6(y-5)=3(10+3y) equation: 



6(y-5)=3(10+3y)

We move all terms to the left:

6(y-5)-(3(10+3y))=0

We add all the numbers together, and all the variables

6(y-5)-(3(3y+10))=0

We multiply parentheses

6y-(3(3y+10))-30=0



We calculate terms in parentheses: -(3(3y+10)), so:

3(3y+10)

We multiply parentheses

9y+30

Back to the equation:

-(9y+30)



We get rid of parentheses

6y-9y-30-30=0

We add all the numbers together, and all the variables

-3y-60=0

We move all terms containing y to the left, all other terms to the right

-3y=60

y=60/-3

y=-20

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