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4(3x+1)=16+10x
We move all terms to the left:
4(3x+1)-(16+10x)=0
We add all the numbers together, and all the variables
4(3x+1)-(10x+16)=0
We multiply parentheses
12x-(10x+16)+4=0
We get rid of parentheses
12x-10x-16+4=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6
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