3(2j+1)=21

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Solution for 3(2j+1)=21 equation:



3(2j+1)=21
We move all terms to the left:
3(2j+1)-(21)=0
We multiply parentheses
6j+3-21=0
We add all the numbers together, and all the variables
6j-18=0
We move all terms containing j to the left, all other terms to the right
6j=18
j=18/6
j=3

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