4(3x+1)+7(x-4)=4

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Solution for 4(3x+1)+7(x-4)=4 equation: 



4(3x+1)+7(x-4)=4

We move all terms to the left:

4(3x+1)+7(x-4)-(4)=0

We multiply parentheses

12x+7x+4-28-4=0

We add all the numbers together, and all the variables

19x-28=0

We move all terms containing x to the left, all other terms to the right

19x=28

x=28/19

x=1+9/19

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