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1/3x-1/4x=1/2+2
We move all terms to the left:
1/3x-1/4x-(1/2+2)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
1/3x-1/4x-2-1/2=0
We calculate fractions
(-48x^2)/48x^2+16x/48x^2+(-12x)/48x^2-2=0
We multiply all the terms by the denominator
(-48x^2)+16x+(-12x)-2*48x^2=0
Wy multiply elements
(-48x^2)-96x^2+16x+(-12x)=0
We get rid of parentheses
-48x^2-96x^2+16x-12x=0
We add all the numbers together, and all the variables
-144x^2+4x=0
a = -144; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-144)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-144}=\frac{-8}{-288} =1/36 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-144}=\frac{0}{-288} =0 $
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