-(1-4a)+7a=a-3(3a-6)

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Solution for -(1-4a)+7a=a-3(3a-6) equation: 



-(1-4a)+7a=a-3(3a-6)

We move all terms to the left:

-(1-4a)+7a-(a-3(3a-6))=0

We add all the numbers together, and all the variables

-(-4a+1)+7a-(a-3(3a-6))=0

We add all the numbers together, and all the variables

7a-(-4a+1)-(a-3(3a-6))=0

We get rid of parentheses

7a+4a-(a-3(3a-6))-1=0



We calculate terms in parentheses: -(a-3(3a-6)), so:

a-3(3a-6)

We multiply parentheses

a-9a+18

We add all the numbers together, and all the variables

-8a+18

Back to the equation:

-(-8a+18)



We add all the numbers together, and all the variables

11a-(-8a+18)-1=0

We get rid of parentheses

11a+8a-18-1=0

We add all the numbers together, and all the variables

19a-19=0

We move all terms containing a to the left, all other terms to the right

19a=19

a=19/19

a=1

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