4(2y+3)=3(5y-2)

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Solution for 4(2y+3)=3(5y-2) equation: 



4(2y+3)=3(5y-2)

We move all terms to the left:

4(2y+3)-(3(5y-2))=0

We multiply parentheses

8y-(3(5y-2))+12=0



We calculate terms in parentheses: -(3(5y-2)), so:

3(5y-2)

We multiply parentheses

15y-6

Back to the equation:

-(15y-6)



We get rid of parentheses

8y-15y+6+12=0

We add all the numbers together, and all the variables

-7y+18=0

We move all terms containing y to the left, all other terms to the right

-7y=-18

y=-18/-7

y=2+4/7

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