7(3a+54)=11(a-1)+19

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Solution for 7(3a+54)=11(a-1)+19 equation: 



7(3a+54)=11(a-1)+19

We move all terms to the left:

7(3a+54)-(11(a-1)+19)=0

We multiply parentheses

21a-(11(a-1)+19)+378=0



We calculate terms in parentheses: -(11(a-1)+19), so:

11(a-1)+19

We multiply parentheses

11a-11+19

We add all the numbers together, and all the variables

11a+8

Back to the equation:

-(11a+8)



We get rid of parentheses

21a-11a-8+378=0

We add all the numbers together, and all the variables

10a+370=0

We move all terms containing a to the left, all other terms to the right

10a=-370

a=-370/10

a=-37

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