144=3(2x+4)x

Solution for 144=3(2x+4)x equation:

144=3(2x+4)x

We move all terms to the left:

144-(3(2x+4)x)=0


We calculate terms in parentheses: -(3(2x+4)x), so:

3(2x+4)x

We multiply parentheses

6x^2+12x

Back to the equation:

-(6x^2+12x)


We get rid of parentheses

-6x^2-12x+144=0

a = -6; b = -12; c = +144;
Δ = b2-4ac
Δ = -122-4·(-6)·144
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-60}{2*-6}=\frac{-48}{-12}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+60}{2*-6}=\frac{72}{-12}
=-6
$