4(2x-8)=1/7(49x=7)

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Solution for 4(2x-8)=1/7(49x=7) equation: 



4(2x-8)=1/7(49x=7)

We move all terms to the left:

4(2x-8)-(1/7(49x)=0



Domain of the equation: 749x!=0

x!=0/749

x!=0

x∈R



We multiply parentheses

8x-(1/749x-32=0

We multiply all the terms by the denominator


8x*749x-32-(1=0

We add all the numbers together, and all the variables

8x*749x=0

Wy multiply elements

5992x^2=0

a = 5992; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5992·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{11984}=0$

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