117=1/2h(10+3)

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Solution for 117=1/2h(10+3) equation: 



117=1/2h(10+3)

We move all terms to the left:

117-(1/2h(10+3))=0



Domain of the equation: 2h(10+3))!=0

h∈R



We add all the numbers together, and all the variables

-(1/2h13)+117=0

We get rid of parentheses

-1/2h13+117=0

We multiply all the terms by the denominator


117*2h13-1=0

Wy multiply elements

234h^13-1=0

We do not support ehpression: h^13

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