2x+10=(6x-13)+(x+1)

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Solution for 2x+10=(6x-13)+(x+1) equation: 



2x+10=(6x-13)+(x+1)

We move all terms to the left:

2x+10-((6x-13)+(x+1))=0



We calculate terms in parentheses: -((6x-13)+(x+1)), so:

(6x-13)+(x+1)

We get rid of parentheses

6x+x-13+1

We add all the numbers together, and all the variables

7x-12

Back to the equation:

-(7x-12)



We get rid of parentheses

2x-7x+12+10=0

We add all the numbers together, and all the variables

-5x+22=0

We move all terms containing x to the left, all other terms to the right

-5x=-22

x=-22/-5

x=4+2/5

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