4(2x-7)+3(1+5x)=8(2x-1)

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Solution for 4(2x-7)+3(1+5x)=8(2x-1) equation: 



4(2x-7)+3(1+5x)=8(2x-1)

We move all terms to the left:

4(2x-7)+3(1+5x)-(8(2x-1))=0

We add all the numbers together, and all the variables

4(2x-7)+3(5x+1)-(8(2x-1))=0

We multiply parentheses

8x+15x-(8(2x-1))-28+3=0



We calculate terms in parentheses: -(8(2x-1)), so:

8(2x-1)

We multiply parentheses

16x-8

Back to the equation:

-(16x-8)



We add all the numbers together, and all the variables

23x-(16x-8)-25=0

We get rid of parentheses

23x-16x+8-25=0

We add all the numbers together, and all the variables

7x-17=0

We move all terms containing x to the left, all other terms to the right

7x=17

x=17/7

x=2+3/7

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