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x/3x+42=2(3x+9)
We move all terms to the left:
x/3x+42-(2(3x+9))=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
x-((2(3x+9)))*3x+42*3x=0
Wy multiply elements
x-((2(3x+9)))*3x+126x=0
We add all the numbers together, and all the variables
127x-((2(3x+9)))*3x=0
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