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3(1+x)-2(2x-3)=4(x+3)
We move all terms to the left:
3(1+x)-2(2x-3)-(4(x+3))=0
We add all the numbers together, and all the variables
3(x+1)-2(2x-3)-(4(x+3))=0
We multiply parentheses
3x-4x-(4(x+3))+3+6=0
We calculate terms in parentheses: -(4(x+3)), so:We add all the numbers together, and all the variables
4(x+3)
We multiply parentheses
4x+12
Back to the equation:
-(4x+12)
-1x-(4x+12)+9=0
We get rid of parentheses
-1x-4x-12+9=0
We add all the numbers together, and all the variables
-5x-3=0
We move all terms containing x to the left, all other terms to the right
-5x=3
x=3/-5
x=-3/5
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