4(2x-5)=29-5(x-3)

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Solution for 4(2x-5)=29-5(x-3) equation: 



4(2x-5)=29-5(x-3)

We move all terms to the left:

4(2x-5)-(29-5(x-3))=0

We multiply parentheses

8x-(29-5(x-3))-20=0



We calculate terms in parentheses: -(29-5(x-3)), so:

29-5(x-3)

determiningTheFunctionDomain
-5(x-3)+29

We multiply parentheses

-5x+15+29

We add all the numbers together, and all the variables

-5x+44

Back to the equation:

-(-5x+44)



We get rid of parentheses

8x+5x-44-20=0

We add all the numbers together, and all the variables

13x-64=0

We move all terms containing x to the left, all other terms to the right

13x=64

x=64/13

x=4+12/13

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