(4y+1)+(3y+32)=180

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Solution for (4y+1)+(3y+32)=180 equation: 



(4y+1)+(3y+32)=180

We move all terms to the left:

(4y+1)+(3y+32)-(180)=0

We get rid of parentheses

4y+3y+1+32-180=0

We add all the numbers together, and all the variables

7y-147=0

We move all terms containing y to the left, all other terms to the right

7y=147

y=147/7

y=21

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