4(2x-1)+3(x+2)=5(x-2)=

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Solution for 4(2x-1)+3(x+2)=5(x-2)= equation: 



4(2x-1)+3(x+2)=5(x-2)=

We move all terms to the left:

4(2x-1)+3(x+2)-(5(x-2))=0

We multiply parentheses

8x+3x-(5(x-2))-4+6=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

11x-(5x-10)+2=0

We get rid of parentheses

11x-5x+10+2=0

We add all the numbers together, and all the variables

6x+12=0

We move all terms containing x to the left, all other terms to the right

6x=-12

x=-12/6

x=-2

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