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4(2x-1)+10=3(x+4)
We move all terms to the left:
4(2x-1)+10-(3(x+4))=0
We multiply parentheses
8x-(3(x+4))-4+10=0
We calculate terms in parentheses: -(3(x+4)), so:We add all the numbers together, and all the variables
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
8x-(3x+12)+6=0
We get rid of parentheses
8x-3x-12+6=0
We add all the numbers together, and all the variables
5x-6=0
We move all terms containing x to the left, all other terms to the right
5x=6
x=6/5
x=1+1/5
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