4(2t-3)-2(t-4)=3(t-3)-1

Solution for 4(2t-3)-2(t-4)=3(t-3)-1 equation:

4(2t-3)-2(t-4)=3(t-3)-1

We move all terms to the left:

4(2t-3)-2(t-4)-(3(t-3)-1)=0

We multiply parentheses

8t-2t-(3(t-3)-1)-12+8=0


We calculate terms in parentheses: -(3(t-3)-1), so:

3(t-3)-1

We multiply parentheses

3t-9-1

We add all the numbers together, and all the variables

3t-10

Back to the equation:

-(3t-10)


We add all the numbers together, and all the variables

6t-(3t-10)-4=0

We get rid of parentheses

6t-3t+10-4=0

We add all the numbers together, and all the variables

3t+6=0

We move all terms containing t to the left, all other terms to the right

3t=-6

t=-6/3

t=-2