3x+2(6-x)=18

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Solution for 3x+2(6-x)=18 equation: 



3x+2(6-x)=18

We move all terms to the left:

3x+2(6-x)-(18)=0

We add all the numbers together, and all the variables

3x+2(-1x+6)-18=0

We multiply parentheses

3x-2x+12-18=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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