4(2s-)=3(s+1)

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Solution for 4(2s-)=3(s+1) equation: 



4(2s-)=3(s+1)

We move all terms to the left:

4(2s-)-(3(s+1))=0

We add all the numbers together, and all the variables

4(+2s)-(3(s+1))=0

We multiply parentheses

8s-(3(s+1))=0



We calculate terms in parentheses: -(3(s+1)), so:

3(s+1)

We multiply parentheses

3s+3

Back to the equation:

-(3s+3)



We get rid of parentheses

8s-3s-3=0

We add all the numbers together, and all the variables

5s-3=0

We move all terms containing s to the left, all other terms to the right

5s=3

s=3/5

s=3/5

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