1/4(12a-28)=1/3(24-12a)

Solution for 1/4(12a-28)=1/3(24-12a) equation:

1/4(12a-28)=1/3(24-12a)

We move all terms to the left:

1/4(12a-28)-(1/3(24-12a))=0


Domain of the equation: 4(12a-28)!=0

a∈R



Domain of the equation: 3(24-12a))!=0

a∈R


We add all the numbers together, and all the variables

1/4(12a-28)-(1/3(-12a+24))=0

We calculate fractions


(3a(-)/(4(12a-28)*3(-12a+24)))+(-4a1/(4(12a-28)*3(-12a+24)))=0


We calculate terms in parentheses: +(3a(-)/(4(12a-28)*3(-12a+24))), so:

3a(-)/(4(12a-28)*3(-12a+24))

We add all the numbers together, and all the variables

3a0/(4(12a-28)*3(-12a+24))

We multiply all the terms by the denominator


3a0

We add all the numbers together, and all the variables

3a

Back to the equation:

+(3a)



We calculate terms in parentheses: +(-4a1/(4(12a-28)*3(-12a+24))), so:

-4a1/(4(12a-28)*3(-12a+24))

We multiply all the terms by the denominator


-4a1

We add all the numbers together, and all the variables

-4a

Back to the equation:

+(-4a)


We get rid of parentheses

3a-4a=0

We add all the numbers together, and all the variables

-a=0

a=0/-1

a=0