8x+3(x-2)=4(x+2)

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Solution for 8x+3(x-2)=4(x+2) equation: 



8x+3(x-2)=4(x+2)

We move all terms to the left:

8x+3(x-2)-(4(x+2))=0

We multiply parentheses

8x+3x-(4(x+2))-6=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

11x-(4x+8)-6=0

We get rid of parentheses

11x-4x-8-6=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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