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4(2r-3)=3(r+1)
We move all terms to the left:
4(2r-3)-(3(r+1))=0
We multiply parentheses
8r-(3(r+1))-12=0
We calculate terms in parentheses: -(3(r+1)), so:We get rid of parentheses
3(r+1)
We multiply parentheses
3r+3
Back to the equation:
-(3r+3)
8r-3r-3-12=0
We add all the numbers together, and all the variables
5r-15=0
We move all terms containing r to the left, all other terms to the right
5r=15
r=15/5
r=3
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