2u+5-5(-3u-1)=3(u-2)

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Solution for 2u+5-5(-3u-1)=3(u-2) equation: 



2u+5-5(-3u-1)=3(u-2)

We move all terms to the left:

2u+5-5(-3u-1)-(3(u-2))=0

We multiply parentheses

2u+15u-(3(u-2))+5+5=0



We calculate terms in parentheses: -(3(u-2)), so:

3(u-2)

We multiply parentheses

3u-6

Back to the equation:

-(3u-6)



We add all the numbers together, and all the variables

17u-(3u-6)+10=0

We get rid of parentheses

17u-3u+6+10=0

We add all the numbers together, and all the variables

14u+16=0

We move all terms containing u to the left, all other terms to the right

14u=-16

u=-16/14

u=-1+1/7

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