Y=9/5z+32

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Solution for Y=9/5z+32 equation:



=9/5Y+32
We move all terms to the left:
-(9/5Y+32)=0
Domain of the equation: 5Y+32)!=0
Y∈R
We get rid of parentheses
-9/5Y-32=0
We multiply all the terms by the denominator
-32*5Y-9=0
Wy multiply elements
-160Y-9=0
We move all terms containing Y to the left, all other terms to the right
-160Y=9
Y=9/-160
Y=-9/160

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