4(2p-6)+5-6=-7-2/5(-20+10p)+2p

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Solution for 4(2p-6)+5-6=-7-2/5(-20+10p)+2p equation: 



4(2p-6)+5-6=-7-2/5(-20+10p)+2p

We move all terms to the left:

4(2p-6)+5-6-(-7-2/5(-20+10p)+2p)=0



Domain of the equation: 5(-20+10p)+2p)!=0

p∈R



We add all the numbers together, and all the variables

4(2p-6)-(-7-2/5(10p-20)+2p)+5-6=0

We add all the numbers together, and all the variables

4(2p-6)-(-7-2/5(10p-20)+2p)-1=0

We multiply parentheses

8p-(-7-2/5(10p-20)+2p)-24-1=0

We multiply all the terms by the denominator


8p*5(10p-20)+2p)-(-24*5(10p-20)+2p)-1*5(10p-20)+2p)-7-2=0

Wy multiply elements

40p^2(1+2p)-(-120p(1+2p)-1*5(10p-20)+2p)-7-2=0



We calculate terms in parentheses: -(-120p(1+2p)-1*5(10p-20)+2p), so:

-120p(1+2p)-1*5(10p-20)+2p

We add all the numbers together, and all the variables

-120p(2p+1)-1*5(10p-20)+2p

We add all the numbers together, and all the variables

2p-120p(2p+1)-1*5(10p-20)

We multiply parentheses

-240p^2+2p-120p-1*5(10p-20)

Wy multiply elements

-240p^2+2p-120p-5p(1

We add all the numbers together, and all the variables

-240p^2-118p-5p(1

Back to the equation:

-(-240p^2-118p-5p(1)



We add all the numbers together, and all the variables

40p^2(2p+1)-(-240p^2-118p-5p1-7-2=0

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