10=2(j-1)+2

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Solution for 10=2(j-1)+2 equation: 



10=2(j-1)+2

We move all terms to the left:

10-(2(j-1)+2)=0



We calculate terms in parentheses: -(2(j-1)+2), so:

2(j-1)+2

We multiply parentheses

2j-2+2

We add all the numbers together, and all the variables

2j

Back to the equation:

-(2j)



We move all terms containing j to the left, all other terms to the right

-2j=-10

j=-10/-2

j=+5

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