n-3-3n+2=6(1+5n)-5(5n-7)

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Solution for n-3-3n+2=6(1+5n)-5(5n-7) equation: 



n-3-3n+2=6(1+5n)-5(5n-7)

We move all terms to the left:

n-3-3n+2-(6(1+5n)-5(5n-7))=0

We add all the numbers together, and all the variables

n-3n-(6(5n+1)-5(5n-7))-3+2=0

We add all the numbers together, and all the variables

-2n-(6(5n+1)-5(5n-7))-1=0



We calculate terms in parentheses: -(6(5n+1)-5(5n-7)), so:

6(5n+1)-5(5n-7)

We multiply parentheses

30n-25n+6+35

We add all the numbers together, and all the variables

5n+41

Back to the equation:

-(5n+41)



We get rid of parentheses

-2n-5n-41-1=0

We add all the numbers together, and all the variables

-7n-42=0

We move all terms containing n to the left, all other terms to the right

-7n=42

n=42/-7

n=-6

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