15x+32=2(10x-7)-5x+46

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Solution for 15x+32=2(10x-7)-5x+46 equation: 



15x+32=2(10x-7)-5x+46

We move all terms to the left:

15x+32-(2(10x-7)-5x+46)=0



We calculate terms in parentheses: -(2(10x-7)-5x+46), so:

2(10x-7)-5x+46

We add all the numbers together, and all the variables

-5x+2(10x-7)+46

We multiply parentheses

-5x+20x-14+46

We add all the numbers together, and all the variables

15x+32

Back to the equation:

-(15x+32)



We get rid of parentheses

15x-15x-32+32=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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