4(2n-7)=6(n+3)

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Solution for 4(2n-7)=6(n+3) equation: 



4(2n-7)=6(n+3)

We move all terms to the left:

4(2n-7)-(6(n+3))=0

We multiply parentheses

8n-(6(n+3))-28=0



We calculate terms in parentheses: -(6(n+3)), so:

6(n+3)

We multiply parentheses

6n+18

Back to the equation:

-(6n+18)



We get rid of parentheses

8n-6n-18-28=0

We add all the numbers together, and all the variables

2n-46=0

We move all terms containing n to the left, all other terms to the right

2n=46

n=46/2

n=23

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