3(n+2)=4(1-n)

Solution for 3(n+2)=4(1-n) equation:

3(n+2)=4(1-n)

We move all terms to the left:

3(n+2)-(4(1-n))=0

We add all the numbers together, and all the variables

3(n+2)-(4(-1n+1))=0

We multiply parentheses

3n-(4(-1n+1))+6=0


We calculate terms in parentheses: -(4(-1n+1)), so:

4(-1n+1)

We multiply parentheses

-4n+4

Back to the equation:

-(-4n+4)


We get rid of parentheses

3n+4n-4+6=0

We add all the numbers together, and all the variables

7n+2=0

We move all terms containing n to the left, all other terms to the right

7n=-2

n=-2/7

n=-2/7