7(2+t)=14(t-3)

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Solution for 7(2+t)=14(t-3) equation: 



7(2+t)=14(t-3)

We move all terms to the left:

7(2+t)-(14(t-3))=0

We add all the numbers together, and all the variables

7(t+2)-(14(t-3))=0

We multiply parentheses

7t-(14(t-3))+14=0



We calculate terms in parentheses: -(14(t-3)), so:

14(t-3)

We multiply parentheses

14t-42

Back to the equation:

-(14t-42)



We get rid of parentheses

7t-14t+42+14=0

We add all the numbers together, and all the variables

-7t+56=0

We move all terms containing t to the left, all other terms to the right

-7t=-56

t=-56/-7

t=+8

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