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2(-2x+1)5x+2=-23
We move all terms to the left:
2(-2x+1)5x+2-(-23)=0
We add all the numbers together, and all the variables
2(-2x+1)5x+25=0
We multiply parentheses
-20x^2+10x+25=0
a = -20; b = 10; c = +25;
Δ = b2-4ac
Δ = 102-4·(-20)·25
Δ = 2100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2100}=\sqrt{100*21}=\sqrt{100}*\sqrt{21}=10\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{21}}{2*-20}=\frac{-10-10\sqrt{21}}{-40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{21}}{2*-20}=\frac{-10+10\sqrt{21}}{-40} $
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